SOLUTION: {{{PQ = (P^2-Q^2)/PQ, EVALUATE (3*2)*(5*4)}}} I TRIED THIS (p^2-Q^2)/PQ = ((P-Q)(P+Q))/pq so [(3*2)-(5*4)][(3*2)+(5*4)]/(3*2)(5*4) it gives -91/30

Algebra ->  Sequences-and-series -> SOLUTION: {{{PQ = (P^2-Q^2)/PQ, EVALUATE (3*2)*(5*4)}}} I TRIED THIS (p^2-Q^2)/PQ = ((P-Q)(P+Q))/pq so [(3*2)-(5*4)][(3*2)+(5*4)]/(3*2)(5*4) it gives -91/30      Log On


   

Question 359043: PQ+=+%28P%5E2-Q%5E2%29%2FPQ%2C+EVALUATE+%283%2A2%29%2A%285%2A4%29 I TRIED THIS
(p^2-Q^2)/PQ = ((P-Q)(P+Q))/pq so [(3*2)-(5*4)][(3*2)+(5*4)]/(3*2)(5*4) it gives
-91/30
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
What are you trying to solve for?
PQ=%28P%5E2-Q%5E2%29%2FPQ
P%5E2-Q%5E2=%28PQ%29%5E2
.
.
.
P=3%2A2=6
Q=5%2A4=20
36-400=%28120%29%5E2
-364=14400
False, so the original equation is not true.