SOLUTION: If n is any integer, then 2n is an even integer and 2n + 1 is an odd integer. Consecutive integers are one right after each other. If n is any integer, then n + 1 would be the n

Algebra ->  Sequences-and-series -> SOLUTION: If n is any integer, then 2n is an even integer and 2n + 1 is an odd integer. Consecutive integers are one right after each other. If n is any integer, then n + 1 would be the n      Log On


   

Question 328803: If n is any integer, then 2n is an even integer and 2n + 1 is an odd integer. Consecutive integers are one right after each other. If n is any integer, then n + 1 would be the next integer and n + 2 would be the next integer and so on.
a.) Find two consecutive odd integers such that the sum of their reciprocals is the fraction 12 over 35
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
1%2Fn%2B1%2F%28n%2B2%29=12%2F35
Multiply both sides by 35n%28n%2B2%29
35%28n%2B2%29%2B35n=12n%28n%2B2%29
35n%2B70%2B35n=12n%5E2%2B24n
12n%5E2-46n-70=0
6n%5E2-23n-35=0
%286n%2B7%29%28n-5%29=0
Only one of the factors will provide an integer solution.
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n-5=0
highlight%28n=5%29
The two integers are 5 and 7.
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Verified,
1%2F5%2B1%2F7=7%2F35%2B5%2F35=12%2F35}