Question 309333: find the 31st term of the aritmctic sequence 23,36,49,.....
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! find the 31st term of the aritmctic sequence 23,36,49,.....
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a(1) = 23
d = 36-23 = 13
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Form: a(n) = 23+(n-1)d
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a(31) = 23 + 30*13
a(31) = 23 + 390
a(31) = 413
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Cheers,
Stan H.
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