SOLUTION: Find -4+((100*(pi^2))/2!)-((2500*(pi^4))/4!)+((62500*(pi^6))/6!)-...

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Question 250953: Find
-4+((100*(pi^2))/2!)-((2500*(pi^4))/4!)+((62500*(pi^6))/6!)-...
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
We can create a formula for the alternating sum. It might look a little messy:
SUM(n=0 to inf.) (-1)^n^2*pi^(2n+2) / (2n+2)factorial(!)
If we sum all of this, we get 8.
Now, -4 + 8 = 4.