SOLUTION: We define the sequence a recursively by setting a_1 = 10 and a_(i+1) = a_i + 4 for all i>= 1. what is the first five terms of this sequence.

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Question 206237: We define the sequence a recursively by setting a_1 = 10 and a_(i+1) = a_i + 4 for all i>= 1. what is the first five terms of this sequence.
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
We define the sequence a recursively by setting
a%5B1%5D+=+10 and a%5Bi%2B1%5D%22%22=+a%5Bi%5D+%2B+4 for all i%3E=+1.
what is the first five terms of this sequence.

We are given a%5B1%5D=10.

Now we substitute i+=+1 into

a%5Bi%2B1%5D+=+a%5Bi%5D+%2B+4 and get

a%5B1%2B1%5D+=+a%5B1%5D+%2B+4

a%5B2%5D+=+a%5B1%5D+%2B+4

and now we substitute a%5B1%5D=10 and get

a%5B2%5D+=+10+%2B+4

a%5B2%5D+=+14

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Now we substitute i+=+2 into

a%5Bi%2B1%5D+=+a%5Bi%5D+%2B+4 and get

a%5B2%2B1%5D+=+a%5B2%5D+%2B+4

a%5B3%5D+=+a%5B2%5D+%2B+4

and now we substitute a%5B2%5D=14 and get

a%5B3%5D+=+14+%2B+4

a%5B3%5D+=+18
 
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Now we substitute i+=+3 into

a%5Bi%2B1%5D+=+a%5Bi%5D+%2B+4 and get

a%5B3%2B1%5D+=+a%5B3%5D+%2B+4

a%5B4%5D+=+a%5B3%5D+%2B+4

and now we substitute a%5B3%5D=18 and get

a%5B4%5D+=+18+%2B+4

a%5B4%5D+=+22

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Now we substitute i+=+4 into

a%5Bi%2B1%5D+=+a%5Bi%5D+%2B+4 and get

a%5B4%2B1%5D+=+a%5B4%5D+%2B+4

a%5B5%5D+=+a%5B4%5D+%2B+4

and now we substitute a%5B4%5D=22 and get

a%5B4%5D+=+22+%2B+4

a%5B4%5D+=+26

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Now we substitute i+=+4 into

a%5Bi%2B1%5D+=+a%5Bi%5D+%2B+4 and get

a%5B4%2B1%5D+=+a%5B4%5D+%2B+4

a%5B5%5D+=+a%5B4%5D+%2B+4

and now we substitute a%5B4%5D=26 and get

a%5B5%5D+=+26+%2B+4

a%5B5%5D+=+30

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So the first five terms are:

a%5B1%5D=10, a%5B2%5D+=+14, a%5B3%5D+=+18, a%5B4%5D+=+26, a%5B5%5D+=+30.

Edwin