SOLUTION: Please help me solve this problem. It says, Decide whether each infinite geometric series diverges or converges. State whether each series has a sum. I understand that it diver

Algebra ->  Sequences-and-series -> SOLUTION: Please help me solve this problem. It says, Decide whether each infinite geometric series diverges or converges. State whether each series has a sum. I understand that it diver      Log On


   



Question 196526: Please help me solve this problem.
It says, Decide whether each infinite geometric series diverges or converges. State whether each series has a sum.
I understand that it diverges when the absolute value of r is > or = 1 and converges when the absolute value of r is < 1, but how do you know whether each series has a sum. For example one problem says:
1. 4 + 2 + 1 + ...
and I know that r=2 therefore it diverges but I can not figure out whether it has a sum or not.
Thanks for your time.

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Well first off, if a series diverges, it does not have a sum (ie the if you add up the infinite terms, you won't get a fixed number).


In this problem, however, the series does converge. Here's why:


The sequence of terms: 4, 2, 1, ... can be modeled by the formula:

a%5Bn%5D=4%2A%281%2F2%29%5En where "n" starts at n=0 (note: plug in some values to test this)


Since this equation fits the form a%5Bn%5D=a%2Ar%5En and r=1%2F2%3C1, this means that the absolute value of "r" is less than 1. So the series converges.


To find the sum of the infinite series, simply use the formula S=a%2F%281-r%29 where "a" is the first term and "r" is given as 1%2F2

So the infinite sum is...

S=4%2F%281-1%2F2%29=4%2F%281%2F2%29=4%282%29=8


In other words,

4+2+1+...=8


I hope this makes sense.