SOLUTION: Can someone help me with this, not sure how to go about this...
Using the formula, n^2=(k(k+1)(2k+1))/6 compute the value of
{{{sum(2m^2+3m-4),m=0,5}}} where m=0 and 5
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Sequences-and-series
-> SOLUTION: Can someone help me with this, not sure how to go about this...
Using the formula, n^2=(k(k+1)(2k+1))/6 compute the value of
{{{sum(2m^2+3m-4),m=0,5}}} where m=0 and 5
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Question 147003: Can someone help me with this, not sure how to go about this...
Using the formula, n^2=(k(k+1)(2k+1))/6 compute the value of where m=0 and 5
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