SOLUTION: Let a + ar + ar^2 + ar^3 + \dotsb be an infinite geometric series. The sum of the series is 9. The sum of the cubes of all the terms is 36. Find the common ratio.

Algebra ->  Sequences-and-series -> SOLUTION: Let a + ar + ar^2 + ar^3 + \dotsb be an infinite geometric series. The sum of the series is 9. The sum of the cubes of all the terms is 36. Find the common ratio.      Log On


   



Question 1209803: Let
a + ar + ar^2 + ar^3 + \dotsb
be an infinite geometric series. The sum of the series is 9. The sum of the cubes of all the terms is 36. Find the common ratio.

Found 2 solutions by CPhill, greenestamps:
Answer by CPhill(1959) About Me  (Show Source):
You can put this solution on YOUR website!
Let's solve this problem step-by-step.
**1. Sum of the Infinite Geometric Series**
* The sum of an infinite geometric series is given by: S = a / (1 - r)
* We are given that the sum is 9: a / (1 - r) = 9
**2. Sum of the Cubes of the Terms**
* The terms of the series are: a, ar, ar², ar³, ...
* Cubing each term: a³, a³r³, a³r⁶, a³r⁹, ...
* This is also a geometric series with:
* First term: a³
* Common ratio: r³
* The sum of this series is: a³ / (1 - r³)
* We are given that this sum is 36: a³ / (1 - r³) = 36
**3. Solve the System of Equations**
* From a / (1 - r) = 9, we get: a = 9(1 - r)
* Substitute this into a³ / (1 - r³) = 36:
* [9(1 - r)]³ / (1 - r³) = 36
* 729(1 - r)³ / (1 - r³) = 36
* (1 - r)³ / (1 - r³) = 36 / 729 = 4 / 81
* Factor (1 - r³):
* (1 - r³) = (1 - r)(1 + r + r²)
* Substitute this into the equation:
* (1 - r)³ / [(1 - r)(1 + r + r²)] = 4 / 81
* (1 - r)² / (1 + r + r²) = 4 / 81
* Take the square root of both sides:
* (1 - r) / √(1 + r + r²) = ± 2 / 9
* We'll assume r is positive, so we'll take the positive root.
* (1 - r) / √(1 + r + r²) = 2 / 9
* 9(1 - r) = 2√(1 + r + r²)
* 81(1 - r)² = 4(1 + r + r²)
* 81(1 - 2r + r²) = 4 + 4r + 4r²
* 81 - 162r + 81r² = 4 + 4r + 4r²
* 77r² - 166r + 77 = 0
* Solve the quadratic equation:
* r = [166 ± √(166² - 4 * 77 * 77)] / (2 * 77)
* r = [166 ± √(27556 - 23716)] / 154
* r = [166 ± √3840] / 154
* r = [166 ± 62.0967] / 154
* We have two possible values for r:
* r1 = (166 + 62.0967) / 154 ≈ 1.481
* r2 = (166 - 62.0967) / 154 ≈ 0.675
* Since the series is convergent, we must have |r| < 1. Therefore, r = 0.675.
**4. Check the Solution**
* r = 0.675 = 27/40
* a = 9(1 - r) = 9(1 - 27/40) = 9(13/40) = 117/40
* a³ / (1 - r³) = (117/40)³ / (1 - (27/40)³) ≈ 36
**Final Answer:** The common ratio is 27/40 or 0.675.

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


a%2Bar%2Bar%5E2+...

That sum is 9

[1] a%2F%281-r%29=9

a%5E3%2Ba%5E3r%5E3%2Ba%5E3r%5E6+...

That sum is 36

[2] a%5E3%2F%281-r%5E3%29=36

From [1],

[3] a%5E3=729%281-r%29%5E3

From [2],

[4] a%5E3=36%281-r%5E3%29

Equating [3] and [4]...

729%281-r%29%5E3=36%281-r%5E3%29
%281-r%5E3%29%2F%281-r%29%5E3=729%2F36=81%2F4

Simplify using 1-r%5E3=%281-r%29%281%2Br%2Br%5E2%29

%28%281-r%29%281%2Br%2Br%5E2%29%29%2F%281-r%29%5E3=81%2F4
%281%2Br%2Br%5E2%29%2F%281-r%29%5E2=81%2F4
81%281-2r%2Br%5E2%29=4%281%2Br%2Br%5E2%29
81-162r%2B81r%5E2=4%2B4r%2B4r%5E2
77r%5E2-166r%2B77=0

Use the quadratic formula to solve; choose the value of r that is less than 1, since both series converge.

r=%28166-sqrt%28166%5E2-4%2877%29%2877%29%29%29%2F154

ANSWER: r = 0.6755342 to several decimal places