SOLUTION: If the second and fifth terms of an G.P are 6 and 48 respectively, find the 10th term of the G.P

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Question 1204372: If the second and fifth terms of an G.P are 6 and 48 respectively, find the 10th term of the G.P
Found 3 solutions by Edwin McCravy, mananth, MathLover1:
Answer by Edwin McCravy(20056) About Me  (Show Source):
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If the second and fifth terms of an G.P. are 6 and 48 respectively, 
find the 10th term of the G.P.

a1, a2=6, a3=6r, a4=48/r, a5=48, a6, a7, a8, a9, a10=??

Since a%5B3%5D%2Ar=a%5B4%5D,

6r%2Ar=48%2Fr
r%5E2=8%2Fr
r%5E3=8
r=2

a%5B6%5D+=+48%2A2=96
a%5B7%5D+=+96%2A2=192
a%5B8%5D+=+192%2A2=384
a%5B9%5D+=+384%2A2=768
a%5B10%5D+=768%2A2=1536

Edwin

Answer by mananth(16946) About Me  (Show Source):
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If the second and fifth terms of an G.P are 6 and 48 respectively, find the 10th term of the G.P
nth. term of GP = an = ar^(n-1)
a5 = 48 - a^(5-1)
-> 48 = ar^4---------------(1)
Similarly
a2 = 6= a^(2-1)
ar =6------------------------(2)
divide (2) by(1)
48/6 = ar^4/ar
r^3=8
r=2
ar =6
but r=2
2a=6
a=3
a10 = ar^9
a10 = 3*2*9 =1536
10th term of the geometric progression is 1536.



Answer by MathLover1(20850) About Me  (Show Source):
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nth term of G.P is

a%5Bn%5D=a%5B1%5D%2Ar%5E%28n-1%29

Given that,
a%5B2%5D=6
a%5B5%5D=48

a%5B2%5D=a%5B1%5D%2Ar%5E%282-1%29
6=a%5B1%5D%2Ar
+a%5B1%5D=6%2Fr.....eq.1

+a%5B5%5D=a%5B1%5D%2Ar%5E%285-1%29
48=a%5B1%5D%2Ar%5E4
a%5B1%5D=48%2Fr%5E4.....eq.2

from eq.1 and eq.2 we have
6%2Fr=48%2Fr%5E4
6r%5E4=48r....simplify
r%5E3=8
r=2

then
a%5B1%5D=6%2F2.....eq.1
a%5B1%5D=3

your nth term equation is
a%5Bn%5D=3%2A2%5E%28n-1%29
now find 10th term

a%5B10%5D=3%2A2%5E%2810-1%29
a%5B10%5D=1536