Question 1198570: A wood man stuck 8k+5log of wood in a pile such that the pile contain k layet .the top layer contain 8logs,each layer contain 1logs than the layer immediately above it . find the value of k .find the total number of logs
Found 3 solutions by ankor@dixie-net.com, greenestamps, ikleyn: Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A wood man stuck 8k+5 logs of wood in a pile such that the pile contain k layers the top layer contain 8 logs, each layer contain 1 log more than the layer immediately above it.
find the value of k.
Each layer adds one log after the top layer so there are 6 layers (+5)
:
find the total number of logs
6 * 8 = 48, plus 5 would give you 53 logs
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I think I messed this one up, adding one to each layer after the top one
would be 8 + 9 + 10 + 11 etc, the total of this = 8k + 5, k is the no. layers
therefore 8k + 5 = total, then 8k = total - 5, I don't how you would get a multiple of 8 with that.
If it was 8k + 6 however,
8k + 6 = 8 + 9 + 10 + 11
8k + 6 = 38
8k = 38 - 6
8k = 32
k = 4
:
Hope this helps, CK
Answer by greenestamps(13200) (Show Source): Answer by ikleyn(52788) (Show Source):
You can put this solution on YOUR website! .
Ignore the post by ankor@dixie-net.com, since his solution is wrong.
To make sure that it is wrong, simply CHECK his answer.
The problem is FATALLY INCORRECT, as tutor @greenestamps explained to you,
and with given numbers CAN NOT be solved : it describes the situation, which NEVER may happen.
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