SOLUTION: the 17 th term of sequence 3, 9, 27, 81, and so on.

Algebra ->  Sequences-and-series -> SOLUTION: the 17 th term of sequence 3, 9, 27, 81, and so on.      Log On


   

Question 1187888: the 17 th term of sequence 3, 9, 27, 81, and so on.
Answer by ikleyn(52787) About Me  (Show Source):
You can put this solution on YOUR website!
.

    a%5B17%5D = a%5B1%5D%2A%289%2F3%29%5E%2817-1%29 = 3%2A3%5E16 = 3%5E17.    ANSWER

Solved, answered and explained.

-----------------

On geometric progressions,  see introductory lessons
    - Geometric progressions
    - The proofs of the formulas for geometric progressions
    - Problems on geometric progressions
    - Word problems on geometric progressions
in this site.

Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic
"Geometric progressions".

Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.