SOLUTION: Hello this is a mathematical induction prove question I need help with. 1. Show that, for every positive integer n: 1 + 2 + 2^2 + 2^3 + … + 2^(n-1) = 2^n - 1

Algebra ->  Sequences-and-series -> SOLUTION: Hello this is a mathematical induction prove question I need help with. 1. Show that, for every positive integer n: 1 + 2 + 2^2 + 2^3 + … + 2^(n-1) = 2^n - 1      Log On


   



Question 1183173: Hello this is a mathematical induction prove question I need help with.

1. Show that, for every positive integer n:
1 + 2 + 2^2 + 2^3 + … + 2^(n-1) = 2^n - 1

Found 2 solutions by Edwin McCravy, robertb:
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!

1+%2B+2+%2B+2%5E2+%2B+2%5E3+%2B+%22%22%2A%22%22%2A%22%22%2A%22%22+%2B+2%5E%28n-1%29%22%22=%22%222%5En+-+1

We show that it's true for n=1.

1%22%22=%22%222%5E1-1%22%22=%22%222-1%22%22=%22%221

Then we find out what would happen if there were some positive integer k,
for which it were true.  If it were true for n = k, then we would have:

1+%2B+2+%2B+2%5E2+%2B+2%5E3+%2B+%22%22%2A%22%22%2A%22%22%2A%22%22+%2B+2%5E%28k-1%29%22%22=%22%222%5Ek+-+1

If that were true, we would be able to add 2k to both sides and
it would still be true.  Then we would have:

1+%2B+2+%2B+2%5E2+%2B+2%5E3+%2B+%22%22%2A%22%22%2A%22%22%2A%22%22+%2B+2%5E%28k-1%29%2B2%5Ek%22%22=%22%222%5Ek+-+1%2B2%5Ek

1+%2B+2+%2B+2%5E2+%2B+2%5E3+%2B+%22%22%2A%22%22%2A%22%22%2A%22%22+%2B2%5Ek%22%22=%22%222%2A2%5Ek+-+1

1+%2B+2+%2B+2%5E2+%2B+2%5E3+%2B+%22%22%2A%22%22%2A%22%22%2A%22%22+%2B2%5Ek%22%22=%22%222%5E1%2A2%5Ek+-+1

1+%2B+2+%2B+2%5E2+%2B+2%5E3+%2B+%22%22%2A%22%22%2A%22%22%2A%22%22+%2B2%5Ek%22%22=%22%222%5E%28k%2B1%29+-+1

That is the original expression with k+1 substituted for n.

So if we could find a positive integer k so that the equation were true,
then we would know that it would have to also be true for the next higher
positive integer.

Now we DO have a positive integer k=1 so that the equation is true! That's
because at the first we showed that it is true when n=k=1, so that means it
is true for n=2.  Now, the fact that it's true for n=2 shows that it's also
true for n=3, and so on and on, through all the positive integers.

Edwin

Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
This is an alternative solution.
It is easy to see by direct multiplication that

(1-x)*(1 + x + x^2 + x^3 +...+ x^(n-1)) = 1 - x^n.

If you let x = 2 in the above equation, you will get

(-1)*(1 + 2 + 2^2 + 2^3 +...+ 2^(n-1)) = 1-2^n

This implies then that

1 + 2 + 2^2 + 2^3 +...+ 2^(n-1) = 2^n -1,

after multiplying both sides of the equation by -1.