SOLUTION: find a n for each geometric sequence a 12 for 96,48,24,

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Question 1179874: find a n for each geometric sequence a 12 for 96,48,24,
Found 2 solutions by mananth, ikleyn:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!

96,48,24,
48/96= 1/2
r =1/2
a1= 96
a12=?
an+=+a%2Ar%5E%28n++-++1%29
a12+=+96%2A+%281%2F2%29%5E11
=23/500

Answer by ikleyn(52788) About Me  (Show Source):
You can put this solution on YOUR website!
.


            The solution and the answer from  @mananth are both  INCORRECT.

            I came to bring a correct solution and the answer.



Geometric progression with the first term 96 and the common ratio of 1%2F2.


The 12-th term is   a%5B12%5D = 96%2F2%5E11 = %283%2A2%5E5%29%2F2%5E11 = 3%2F2%5E6 = 3%2F64..   ANSWER

Solved (correctly).