SOLUTION: Consider each given sequence start. i) Classify each as arithmetic, geometric, and/or none of these. ii) Find the 28th term. iii) Find the sum of the first 7 terms, call it S7

Algebra ->  Sequences-and-series -> SOLUTION: Consider each given sequence start. i) Classify each as arithmetic, geometric, and/or none of these. ii) Find the 28th term. iii) Find the sum of the first 7 terms, call it S7      Log On


   



Question 1178152: Consider each given sequence start. i) Classify each as arithmetic, geometric, and/or none of these. ii) Find the 28th term. iii) Find the sum of the first 7 terms, call it S7 .

a) 44, −6, 44, −4,

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
44,-6, 44, -4,...
1st term a%5B1%5D=44
2nd term a%5B2%5D=-6=44-50
3rd term a%5B3%5D=-4=44-48
=> no common difference is d
r=-4%2F44=-1%2F11
r=44%2F-6=-22%2F3
=> no common ratio r
i) Classify each as arithmetic, geometric, and/or none of these.
=> no common difference d, no common ratio r
so, the sequence is neither arithmetic nor geometric
to find nth term formula use differences:
44........-6........44........-4

................50..................50.....................48..................
.............................0..................2..................
....................................2..................=>3rd difference, so nth term formula
will be 3rd degree function


a%5Bn%5D=an%5E3%2Bbn%5E2%2Bcn%2Bd
plug in some of the values from the sequence, and then solving the resulting system of equations

a%5Bn%5D=an%5E3%2Bbn%5E2%2Bcn%2Bd.......44->first term, so n=1
44=a%2A1%5E3%2Bb%2A1%5E2%2Bc%2A1%2Bd
44=a%2Bb%2Bc%2Bd........eq.1
a%5Bn%5D=an%5E3%2Bbn%5E2%2Bcn%2Bd.......-6->first term, so n=2
-6=a%2A2%5E3%2Bb%2A2%5E2%2Bc%2A2%2Bd
-6=8a%2B4b%2B2c%2Bd............eq.2
44=a%2A3%5E3%2Bb%2A3%5E2%2Bc%2A3%2Bd
44=27a%2B9b%2B3c%2Bd........eq.3
-4=a%2A4%5E3%2Bb%2A4%5E2%2Bc%2A4%2Bd
-4=64a%2B16b%2B4c%2Bd............eq.4


subtract eq.1 from eq.2
-6-44=+8a%2B4b%2B2c%2Bd+-%28a%2Bb%2Bc%2Bd%29
-50=+8a%2B4b%2B2c%2Bd+-a-b-c-d%29
-50=+7a%2B3b%2Bc.............eq.3
subtract eq.1 from eq.3 (reason: next term is 44 again)
44-44=+27a%2B9b%2B3c%2Bd-%28a%2Bb%2Bc%2Bd%29
0=+27a%2B9b%2B3c%2Bd-a-b-c-d
0=+26a%2B8b%2B2c.......solve for b
-26a-2c=8b
b=-26a%2F8-2c%2F8
b=-13a%2F4-c%2F4.............eq.4


go to
-50=+7a%2B3%28-13a%2F4-c%2F4%29%2Bc........eq.3...., substitute b
-50=+c%2F4+-+%2811a%29%2F4......solve for c
-50%2B%2811a%29%2F4=c%2F4
-200%2B11a=c.......................eq.5
go to

b=-13a%2F4-c%2F4.............eq.4, substitute c
b=-13a%2F4-%28-200%2B11a%29%2F4
b=50+-+6a.................eq.6

subtract eq.1 from eq.4
-4-44=64a%2B16b%2B4c%2Bd-%28a%2Bb%2Bc%2Bd%29............substitute b from eq.6 and c from eq.5
-4-44=64a%2B16b%2B4c%2Bd-a-b-c-d
-48=63a%2B15b%2B3c+
-48=63a%2B15%2850+-+6a%29%2B3%28-200%2B11a%29+
-48=63a%2B750+-+90a-600%2B33a+ ....solve for a
-48=6a%2B150
6a=-48-150
6a=-198
a=-33

go to
b=50+-+6a.................substitute a
b=50+-+6%28-33%29
b=50+%2B+198
b=248

go to
-200%2B11a=c........................substitute a
-200%2B11%28-33%29=c
-200-363=c
c=-563
go to
44=a%2Bb%2Bc%2Bd........eq.1substitute a,b, and c
44=-33%2B248-563%2Bd
44=-348%2Bd
44%2B348=d
d=392

so, coefficients are:
a+=+-33, b+=+248, c+=+-563, d+=+392

and equation is:
a%5Bn%5D=-33n%5E3%2B248n%5E2-563n%2B392


ii) Find the 28th term.

a%5B28%5D=-33%2A28%5E3%2B248%2A28%5E2-563%2A28%2B392
a%5B28%5D=-545356



iii) Find the sum of the first 7+terms, call it S7 .
we have 44,-6, 44, -4,...
first find 5th, 6th, and 7th term
a%5B5%5D=-33%2A5%5E3%2B248%2A5%5E2-563%2A5%2B392=-348
a%5B6%5D=-33%2A6%5E3%2B248%2A6%5E2-563%2A6%2B392=-1186
a%5B7%5D=-33%2A7%5E3%2B248%2A7%5E2-563%2A7%2B392=-2716
44,-6, 44, -4,-348,-2716,-2716

the sum is S%5B7%5D=44-6%2B44-4-348-2716-2716+=-5702