SOLUTION: Consider the sequence 6,6,2,-6,-18....show that -6838 is in the sequence

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Question 1177330: Consider the sequence 6,6,2,-6,-18....show that -6838 is in the sequence
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

we need to find n-th term formula, so first find differences
6........6........2........-6........-18
....0........4........-8........-12...........
.........-4.......-4........-4........................
if we look at the second difference they go up in steps of -4+
the next number in second row is -12%2B%28-4%29=-16
the next number in first row is -18%2B%28-16%29=-34
since second differences are equal, we conclude this is a quadratic sequence
n-th term formula is:
a%5Bn%5D=an%5E2%2Bbn%2Bc
to find a+divide second difference by 2
a=-4%2F2=-2
now we have
a%5Bn%5D=-2n%5E2%2Bbn%2Bc
substitute n=1 and n=2 in formula above to get formulas for first two terms
a%5B1%5D=-2%2A1%5E2%2Bb%2A1%2Bc
a%5B2%5D=-2%2A2%5E2%2Bb%2A2%2Bc
so, we have
a%5B1%5D=-2%2Bb%2Bc
a%5B2%5D=-8%2B2b%2Bc
use first two terms
6=-2%2Bb%2Bc ............1)
6=-8%2B2b%2Bc............2)
----------------------subtract 1) from 2)
6-6=-8%2B2b%2Bc+-%28-2%2Bb%2Bc+%29
0=-8%2B2b%2Bc%2B2-b-c+
0=-6%2Bb
b=6
go to
6=-2%2Bb%2Bc ............1), substitute b
6=-2%2B6%2Bc++
6=4%2Bc
c=6-4
c=2
and your formula is:
a%5Bn%5D=-2n%5E2%2B6n%2B2
now check if -6838 is in the sequence
-6838=-2n%5E2%2B6n%2B2 ...........solve for n, the number of that term
2n%5E2+-+6n+-+6840+=+0 ...........simplify

n%5E2+-+3n+-+3420+=+0 ........using quadratic formula x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ we get
n=-57 or+n=60
disregard negative solution, so
n=60 and 60th term is -6838