SOLUTION: In the continuation of this array of positive integers, in which column is the number 12000? A) 99 B) 100 C) 101 D) 102 E) 103 https://ibb.co/KG8z40Y

Algebra ->  Sequences-and-series -> SOLUTION: In the continuation of this array of positive integers, in which column is the number 12000? A) 99 B) 100 C) 101 D) 102 E) 103 https://ibb.co/KG8z40Y      Log On


   

Question 1171273: In the continuation of this array of positive integers, in which column is the number 12000?
A) 99
B) 100
C) 101
D) 102
E) 103
https://ibb.co/KG8z40Y
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!


It appears that all even squares - except 1 - will terminate in the 1st column
The next perfect square after 12000 is 12100
The square root of 12100+is 110
So, we will have a square that will have 110 integers on each side
12100+will be in the 1st column.....
12109 will be in the second column = 12100+-+12109+%2B+1+=+2
12108 will be in the 3rd column = 12100+-+12108+%2B+1+=+3

So, to find the column containing 12000 we can evaluate this
12100+-+12000+%2B+1+ =
100+%2B+1+ =
101+
Answer: C) 101
The number 12000 will be in column 101 (and row 110).