SOLUTION: The question asks to find the number of terms 11+17+...+365

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Question 1168804: The question asks to find the number of terms
11+17+...+365

Found 2 solutions by math_helper, ikleyn:
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!

Common difference is 6: +%28365-11%29%2F6+%2B+1+ is the number of terms
Use your calculator

Answer by ikleyn(52794) About Me  (Show Source):
You can put this solution on YOUR website!
.


            In such problem,  good wording explanation and clear understanding weight more than formal formulas.



You have an arithmetic progression with the common difference of  6.

The number of equal gaps between the endpoints  11  and  365  is     %28365-11%29%2F6 = 59.

The number of terms is the number of gaps plus one,  i.e.   59+1 = 60.        ANSWER

Solved.

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For introductory lessons on arithmetic progressions see
    - Arithmetic progressions
    - The proofs of the formulas for arithmetic progressions
    - Problems on arithmetic progressions
    - Word problems on arithmetic progressions
    - Finding number of terms of an arithmetic progression
in this site.

Pay special attention to the last lesson in this list, since it is most relevant to your problem.


Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Arithmetic progressions".


Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.