SOLUTION: show tha the sum of n terms of the progression; logx, logx^2, logx^3, logx^4, ... Is n[n+1/2] logx

Algebra ->  Sequences-and-series -> SOLUTION: show tha the sum of n terms of the progression; logx, logx^2, logx^3, logx^4, ... Is n[n+1/2] logx      Log On


   

Question 1162608: show tha the sum of n terms of the progression;
logx, logx^2, logx^3, logx^4, ... Is

n[n+1/2] logx
Answer by ikleyn(52787) About Me  (Show Source):
You can put this solution on YOUR website!
.

It is  %28n%28n%2B1%29%2F2%29%2Alog%28x%29,  INSTEAD.


Fix the error in your post (!)



It is the sum of the arithmetic progression


    log(x) + 2*log(x) + 3*log(x) + . . . + n*log(x) = log(x)*(1 + 2 + 3 + . . . + n) = %28n%28n%2B1%29%2F2%29%2Alog%28x%29.

Solved.