SOLUTION: Find the fifth term of the sequence. a(n) = 4a[(sub)n-1]+3, a(1) = 3 (n-1) is in subscript after 4a. I hope that makes sense. I tried using some of the formulas that I was g

Algebra ->  Sequences-and-series -> SOLUTION: Find the fifth term of the sequence. a(n) = 4a[(sub)n-1]+3, a(1) = 3 (n-1) is in subscript after 4a. I hope that makes sense. I tried using some of the formulas that I was g      Log On


   



Question 1158967: Find the fifth term of the sequence.
a(n) = 4a[(sub)n-1]+3, a(1) = 3
(n-1) is in subscript after 4a. I hope that makes sense. I tried using some of the formulas that I was given in class and can't seem to find one that works for me. Thank you so much in advance. <3

Found 2 solutions by solver91311, MathTherapy:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!








Follow the pattern to calculate the remaining two terms you need.


John

My calculator said it, I believe it, that settles it


Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Find the fifth term of the sequence.
a(n) = 4a[(sub)n-1]+3, a(1) = 3
(n-1) is in subscript after 4a. I hope that makes sense. I tried using some of the formulas that I was given in class and can't seem to find one that works for me. Thank you so much in advance. <3
matrix%282%2C3%2C+a%5Bn%5D%2C+%22=%22%2C+4a%5Bn+-+1%5D+%2B+3%2C+a%5B1%5D%2C+%22=%22%2C+3%29                    
Have you gotten the gist of this yet?