Question 1151985: 1.Find the nth term of.
1, 5/7, 7/15, 9/31,....
Answer by greenestamps(13200)   (Show Source):
You can put this solution on YOUR website!
Technically, this problem is invalid. There is an APPARENT pattern; but there might be other patterns in the given sequence of numbers that might produce different n-th terms.
To find the pattern I see -- and thus be able to write a formula for the n-th term -- first look at the numerators of the 2nd through 4th terms:
5, 7, 9, ...
Working backwards in that pattern, the 1st term should be 3. So rewrite the first term "1" as a fraction with numerator 3. Then the sequence is
3/3, 5/7, 7/15, 9/31, ...
We have already looked at the pattern for the numerators:
3, 5, 7, 9, ..., 2n+1
I leave it to you to find the pattern in the denominators:
3, 7, 15, 31, ..., ???
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