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The 4-th term = sum of the first 4 terms MINUS sum of the first 3 terms =
= (4^2-3*4) - (3^2-3*3) = (16-12) - (9-9) = 4 - 0 = 4. ANSWER
The n-th term = sum of the first "n" terms MINUS sum of the first (n-1) terms =
= (n^2-3*n) - ((n-1)^2-3*(n-1)).
Simplify to get the answer.