SOLUTION: x,2x+1,11 are three consecutive terms of an arithmetic sequence. Calculate(i) x.(ii) the 30th term.

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Question 1127070: x,2x+1,11 are three consecutive terms of an arithmetic sequence. Calculate(i) x.(ii) the 30th term.
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x,2x+1,11 are three consecutive terms of an arithmetic sequence. Calculate(i) x.(ii) the 30th term.
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x,2x+1,11 are the first three terms of an arithmetic sequence. Calculate(i) x.(ii) the 30th term.
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x + d = 2x + 1 —> d = x + 1 (1)
(2x + 1) + d = 11 —> d = 10 - 2x (2)

Set (1) equal to (2): x + 1 = 10 - 2x
3x = 9
x = 3

d = x + 1 —> d = 4

(i) highlight%28+x=3+%29+

(ii) To find an answer, it must be assumed that the three terms given are the FIRST three terms (or at least their position m must be given) of the sequence (the problem statement does not provide sufficient information).
+a%5B1%5D+=+3+
+a%5B2%5D+=+3%2B4+=+7+
+a%5B3%5D+=+3%2B2%2A4+=+11+
...
+a%5Bn%5D+=+3+%2B+%28n-1%29%2A4+

Plugging in n=30:
+a%5B30%5D+=+3+%2B+%2829%29%2A4+=+3%2B116+=+highlight%28+119+%29+