SOLUTION: S(x)=1+5(x−5)+25(x−5)^2+125(x−5)^3+⋯. Giving your answer as an interval, find all values of x for which the series converges. Now assuming that x is wit

Algebra ->  Sequences-and-series -> SOLUTION: S(x)=1+5(x−5)+25(x−5)^2+125(x−5)^3+⋯. Giving your answer as an interval, find all values of x for which the series converges. Now assuming that x is wit      Log On


   



Question 1121032: S(x)=1+5(x−5)+25(x−5)^2+125(x−5)^3+⋯.
Giving your answer as an interval, find all values of x for which the series converges.
Now assuming that x is within that interval above, find a simple formula for S(x)

Answer by ikleyn(52788) About Me  (Show Source):
You can put this solution on YOUR website!
.
S(x) is the sum of the infinite geometric progression with the first term of 1 and the common ratio of  r = 5*(x-5).


Such a progression converges  if and only if  |r| < 1,  which gives


|5*(x-5)| < 1,   or


|x-5| < 1%2F5,   or


-1%2F5 < x -5 < 1%2F5,   or, equivalently


4.8 < x < 5.2.


Answer.  The convergence domain is  the interval  (4.8,5.2).