SOLUTION: Please help me. 2p+3, 4p+3, and 5p+2 are the first three terms in an arithmetic sequence. How to find p?
Thank you.
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-> SOLUTION: Please help me. 2p+3, 4p+3, and 5p+2 are the first three terms in an arithmetic sequence. How to find p?
Thank you.
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Question 1112962: Please help me. 2p+3, 4p+3, and 5p+2 are the first three terms in an arithmetic sequence. How to find p?
Thank you. Found 2 solutions by ikleyn, rothauserc:Answer by ikleyn(52788) (Show Source):
If three numbers , and form an arithmetic progression, then
- = - ,
by the definition of an arithmetic progression.
It gives you an equation, in your case,
(5p+2) - (4p+3) = (4p+3) - (2p+3).
Simplify and solve for "p".
Then, having "p", restore the three numbers.
You can put this solution on YOUR website! the formula for the nth term of an arithmetic sequence is
:
x(n) = a + d(n-1), where a is the first term and d is the common difference
:
x(1) = a + d(1-1) = a, therefore
:
a = 2p +3
:
we see that the second term ( x(2) ) is
:
4p +3 = 2p +3 +d
:
solve for d
:
d = 2p
:
x(3) is
:
5p +2 = 2p +3 +2p(2)
:
solve for p
:
5p +2 = 6p +3
:
*******
p = -1
*******
:
therefore, a=1, d=-2 and the sequence is
:
1, -1, -3
: