SOLUTION: The 13th and 7th terms of an arithmetic sequence are 15 and 51 respectively
Which term is equal to-21?
Show that 66 is not a term of the sequence
Algebra ->
Sequences-and-series
-> SOLUTION: The 13th and 7th terms of an arithmetic sequence are 15 and 51 respectively
Which term is equal to-21?
Show that 66 is not a term of the sequence
Log On
Question 1109441: The 13th and 7th terms of an arithmetic sequence are 15 and 51 respectively
Which term is equal to-21?
Show that 66 is not a term of the sequence Found 2 solutions by josgarithmetic, greenestamps:Answer by josgarithmetic(39618) (Show Source):
You can put this solution on YOUR website! From term #7 to term #13 is six common differences.
Index 7, term 51.
Index 13, term 15.
-
If first term is A,
then is general term;
General Term,
.
.
.
********MISTAKE*****MISMATCHED INDICES WITH TERMS****************
common difference d,
-
A, initial term , general term
-
-
General Term:
Which term is ? -------solve for n.
Is 66 one of the terms? -------should find n is NOT an integer and NOT a whole number.
An arithmetic error in the beginning of the work shown by the other tutor makes the rest of her response incorrect....
It is 6 more terms from the 7th to the 13th; the value changes from 51 to 15, a decrease of 36. So the common difference is -36/6 = -6.
-21 is 36 less than 15, which is the 13th term. You could use the common difference of -6 to determine which term is -21. However, we already know that the difference is 36 when the terms are 6 terms apart. So the term that is -21 is term #(13+6), or term 19.
The difference between 66 and 51 is 15, which is not a multiple of 6; therefore since 51 is a term of the sequence, 66 is not.