SOLUTION: If n(A) = 4, n(B) = 5, and n(C) = 6, what is the greatest and least number of elements possible in AᑎBᑎC?
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Sequences-and-series
-> SOLUTION: If n(A) = 4, n(B) = 5, and n(C) = 6, what is the greatest and least number of elements possible in AᑎBᑎC?
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Suppose:
A = {a,b,c,d}
B = (a,b,c,d,e}
C = {a,b,c,d,e,f}
Then AᑎBᑎC = {a,b,c,d} has a maximum of 4 elements.
Suppose:
A = {a,b,c,d}
B = (e,f,g,h,i}
C = {j,k,l,m,n,o}
Then AᑎBᑎC = Ø (the empty set) has a minimum of no elements.
Edwin