SOLUTION: A geometric sequence has a first term of 768 and the second term is 576. I need to find the LEAST value of n such that the nth term of the sequence is less than 7. I found that

Algebra ->  Sequences-and-series -> SOLUTION: A geometric sequence has a first term of 768 and the second term is 576. I need to find the LEAST value of n such that the nth term of the sequence is less than 7. I found that      Log On


   

Question 1104451: A geometric sequence has a first term of 768 and the second term is 576.
I need to find the LEAST value of n such that the nth term of the sequence is less than 7.
I found that r=0.75?
Do I use the formula ar^n-1?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
First term being 768, and r=3%2F4, then general term 768%2A%283%2F4%29%5E%28n-1%29

What n so that term less than 7?
768%280.75%29%5E%28n-1%29%3C7
.
.
.

Answer by ikleyn(52788) About Me  (Show Source):
You can put this solution on YOUR website!
.
Please do not tell that you found r = 0.75.


It was ME who found it for you under this link

https://www.algebra.com/algebra/homework/Sequences-and-series/Sequences-and-series.faq.question.1104433.html

https://www.algebra.com/algebra/homework/Sequences-and-series/Sequences-and-series.faq.question.1104433.html