SOLUTION: In the sequence -12, -7, -2, 3, 8, 13,...determine the 90th term and the sum of the first 80 terms.

Algebra ->  Sequences-and-series -> SOLUTION: In the sequence -12, -7, -2, 3, 8, 13,...determine the 90th term and the sum of the first 80 terms.      Log On


   



Question 1101405: In the sequence -12, -7, -2, 3, 8, 13,...determine the 90th term and the sum of the first 80 terms.
Found 2 solutions by josgarithmetic, stanbon:
Answer by josgarithmetic(39617) About Me  (Show Source):
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Common difference of 5, increasing sequence.

General term, -12%2B5%28n-1%29 for index, n.
You can determine the n=90 term from that.


Sum of first 80 terms:
%2880%2F2%29%28-12%2B%28-12%2B5%2880-1%29%29%29------simplify and compute this.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
In the sequence -12, -7, -2, 3, 8, 13,...determine the 90th term and the sum of the first 80 terms.
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Arithmetic sequence with d = -7-(-12) = 5 and a(1) = -12
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a(90) = -12 + (89)5 = 433
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Sum of 1st 80::
S(80) = (80/2) * (-12+a(80))
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But, a(80) = -12 + 79*5 = 383
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So, S(80) = 40*(-12+383) = 14840
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Cheers,
Stan H.