SOLUTION: Given a geometric sequence where t3=17 and t6=136, t7 would be

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Question 1097539: Given a geometric sequence where t3=17 and t6=136, t7 would be
Answer by ikleyn(52788) About Me  (Show Source):
You can put this solution on YOUR website!
.
t7  is  136*2.


Why ?


Try to solve it on your own.   Notice that  136%2F17 = 8 = 2%5E3.


All you need to know is   "WHAT A GEOMETRIC PROGRESSION IS ?".


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On geometric progressions, see introductory lessons in this site
    - Geometric progressions
    - The proofs of the formulas for geometric progressions
    - Problems on geometric progressions
    - Word problems on geometric progressions
    - Solved problems on geometric progressions


Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Geometric progressions".


Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.