SOLUTION: evaluate 1+3^2+3^3+..++..3^60 everything divided by 3^61-1

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Question 1096429: evaluate 1+3^2+3^3+..++..3^60 everything divided by 3^61-1
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!

The expression as you show it is

(1+3^2+3^3+...+3^60)/(3^61-1)

I suspect you have omitted one term from the numerator, so that the expression is supposed to be

(1+3+3^2+3^3+...+3^60)/(3^61-1)

If that is indeed what the expression is supposed to be then the formula for the sum of a finite geometric series tells us that the numerator is equivalent to
%283%5E61-1%29%2F%283-1%29+=+%283%5E61-1%29%2F2
and so the entire expression is equal to
%28%283%5E61-1%29%2F2%29%2F%283%5E61-1%29+=+1%2F2