SOLUTION: If 25/k = 1^2 -2^2/5 + 3^2/5^2 - 4^2/5^3+.......infinity , then what is the value of k?

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Question 1094569: If 25/k = 1^2 -2^2/5 + 3^2/5^2 - 4^2/5^3+.......infinity ,
then what is the value of k?

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
If 25/k = 1^2 -2^2/5 + 3^2/5^2 - 4^2/5^3+.......infinity ,
then what is the value of k?
25%2Fk%22%22=%22%22

25%2Fk%22%22=%22%22

Multiply through by 5

125%2Fk%22%22=%22%22

Add the two preceding sequences:

150%2Fk%22%22=%22%22

150%2Fk%22%22=%22%22

150%2Fk%22%22=%22%222+%2B+5%2F5%5E1+-+7%2F5%5E2%2B9%2F5%5E3-11%2F5%5E4%2B%22%22%2A%22%22%2A%22%22%2A%22%22

150%2Fk%22%22=%22%222+%2B+1+-+7%2F5%5E2%2B9%2F5%5E3-11%2F5%5E4%2B%22%22%2A%22%22%2A%22%22%2A%22%22

150%2Fk%22%22=%22%223+-+7%2F5%5E2%2B9%2F5%5E3-11%2F5%5E4%2B%22%22%2A%22%22%2A%22%22%2A%22%22

Multiply by 5

750%2Fk%22%22=%22%2215+-+7%2F5%5E1%2B9%2F5%5E2-11%2F5%5E3%2B13%2F5%5E4-%22%22%2A%22%22%2A%22%22%2A%22%22

Add the two preceding sequences:

900%2Fk%22%22=%22%2218+-+7%2F5%2B2%2F5%5E2-2%2F5%5E3%2B2%2F5%5E4-%22%22%2A%22%22%2A%22%22%2A%22%22

900%2Fk%22%22=%22%2283%2F5%2B2%2F5%5E2-2%2F5%5E3%2B2%2F5%5E4-%22%22%2A%22%22%2A%22%22%2A%22%22

From the 2nd term on the right onward is an infinite geometric series
 with  a%5B1%5D=2%2F5%5E3 and r=-1%2F5, so we use the formula:

         S%5Binfinity%5D%22%22=%22%22a%5B1%5D%2F%281-r%29

900%2Fk%22%22=%22%2283%2F5%2B%282%2F5%5E2%29%2F%281-%28-1%2F5%29%29

900%2Fk%22%22=%22%2283%2F5%2B%282%2F25%29%2F%281%2B1%2F5%29

900%2Fk%22%22=%22%2283%2F5%2B%282%2F25%29%2F%286%2F5%29

900%2Fk%22%22=%22%2283%2F5%2B%282%2F25%29%2A%285%2F6%29

900%2Fk%22%22=%22%2283%2F5%2B1%2F15

900%2Fk%22%22=%22%2250%2F3

Divide both sides by 50

18%2Fk%22%22=%22%221%2F3

Cross-multiply:

k%22%22=%22%2254

Edwin