SOLUTION: The sum to infinity of a geometric sequence is 27/2 while the sum of the first three terms is 13. Find the sum of the first 5 terms. Thank you for your help.

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Question 1090598: The sum to infinity of a geometric sequence is 27/2 while the sum of the first three terms is 13. Find the sum of the first 5 terms.
Thank you for your help.

Answer by ikleyn(52788) About Me  (Show Source):
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The sum to infinity of a geometric sequence is 27/2 while the sum of the first three terms is 13. Find the sum of the first 5 terms.
Thank you for your help.
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We have 

S = a+%2B+aq+%2B+aq%5E2+%2B+aq%5E3+%2B+aq%5E4+%2B+aq%5E5+%2B+ellipsis = %28a+%2B+aq+%2B+aq%5E2%29 + %28aq%5E3+%2B+aq%5E4+%2B+aq%5E5+%2B+ellipsis%29 = %28a+%2B+aq+%2B+aq%5E2%29 + q%5E3%2A%28a+%2B+aq+%2B+aq%5E2+%2B+ellipsis%29   (1)


Notice that the infinite sum in parentheses of the right-most side is S, again.   // It is the KEY IDEA #1.


Based on given info, replace in (1)  S  by 27%2F2  and replace the sum of the first three terms by 13. You will get

27%2F2 = 13+%2B+q%5E3%2AS,    or, which is the same

1%2F2 = q%5E3%2AS.    (2).


In (2),  replace S by  27%2F2  as it is given.  // It is the KEY IDEA #2.


You will get   1%2F2 = q%5E3%2A%2827%2F2%29,   which implies   q%5E3 = 1%2F27.


Hence,  q = 1%2F3.   Thus we just found the common ratio of the progression;  it is  q = 1%2F3. 


Now we are at the finish line.


Similar to (1), we have

S = a+%2B+aq+%2B+aq%5E2+%2B+aq%5E3+%2B+aq%5E4+%2B+aq%5E5+%2B+aq%5E6+%2B+aq%5E7+%2B+ellipsis = %28a+%2B+aq+%2B+aq%5E2+%2B+aq%5E3+%2B+aq%5E4%29 + %28aq%5E5+%2B+aq%5E6+%2B+aq%5E7+%2B+ellipsis%29 = %28a+%2B+aq+%2B+aq%5E2+%2B+aq%5E3+%2B+a%5E4%29 + q%5E5%2A%28a+%2B+aq+%2B+aq%5E2+%2B+ellipsis%29   (3)


You can re-write it as


S = S%5B5%5D + q%5E5%2AS,     (4)      // It is the KEY IDEA #3.


where S%5B5%5D  is the sum of the first 5 terms, which is under the question.

Now from (4)

S%5B5%5D = S+-+q%5E5%2AS = S%2A%281-q%5E5%29 = %2827%2F2%29%2A%281+-+%281%2F3%29%5E5%29 = %2827%2F2%29%2A%281-1%2F243%29 = %2827%2F2%29%2A%28242%2F243%29 = %2827%2F243%29%2A%28242%2F2%29 = %281%2F9%29%2A121 = 121%2F9 = 13 4%2F9.

Answer. The sum of the first 5 terms of the given GP is 13 4%2F9.


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