Question 1088543: Given an arithmetic sequence -11,2,15..., if T(m) is the first term that exceeds 200, find the value of m.
Answer by rothauserc(4718)   (Show Source):
You can put this solution on YOUR website! -11,2,15...
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200 = -11 + 13(m-1)
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13(m-1) = 211
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13m -12 = 211
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13m = 223
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m = 17
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for m = 17
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T(17) = -11 +13(17-1) = 197
T(18) = -11 +13(18-1) = 210
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m = 18, T(18) = 210 > 200, is first term that exceeds 200
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