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Given the arithmetic series 2+4+6...=420 find the term a and the common difference
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1. The common difference is 2.
2. To find the number of terms, first cancel the given equality by 2. You will get
1 + 2 + 3 + . . . + = 210.
Or, which is the same,
= 210,
n*(n+1) = 420.
420 decomposes into the product of two consecutive natural integers by an unique way: 420 = 20*21.
Answer. The common difference is 2.
The number of terms is 20.
The 20-th term is = 2 + 2*(20-1) = 2 + 38 = 40.