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Question on Arithmetic Progression (AP)
Find the S15 if T4 = 15 and T9 = 30
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You are given
T4 = 15 = T1 + 3*d, (1)
T9 = 30 = T1 + 8*d. (2)
Distract (1) from (2) and get 5d = 15, d = 3.
Then from (1) find T1 = 15 - 3*d = 15 - 9 = 6.
So, your AP has the first term T1 = 6 and the common difference 3.
Now apply the formula for the sum of AP.