SOLUTION: what would be the formula for 1/2,1,2,4,8. pattern

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Question 1046683: what would be the formula for 1/2,1,2,4,8. pattern
Found 2 solutions by ikleyn, Edwin McCravy:
Answer by ikleyn(52787) About Me  (Show Source):
You can put this solution on YOUR website!
.
a%5Bn%2B1%5D = 2%2Aa%5Bn%5D, n = 1, 2, 3, . . .

Geometric progression, first term 1%2F2, common ratio 2.

On geometric progressions, see the lessons
    - Geometric progressions
    - The proofs of the formulas for geometric progressions
    - Problems on geometric progressions
    - Word problems on geometric progressions
    - Mathematical induction and geometric progressions
    - One characteristic property of geometric progressions
    - Solved problems on geometric progressions
in this site.


Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
We start with 1st term 1/2
To get the 2nd term, we multiply the 1st term 1/2 by 2 
   and get the 2nd term 1.
To get the 3rd term, we multiply the 2nd term 1 by 2 
   and get the 3rd term 2.
To get the 4th term, we multiply the 3rd term 2 by 2 
   and get the 4th term 4.
To get the 5th term, we multiply the 4th term 4 by 2 
   and get the 5th term 8.

So the nth term is 1/2 multiplied by 2 the number of 
times which is one less than the number of the term.

term%5Bn%5D%22%22=%22%22%281%2F2%29%2A%282%29%5E%28n-1%29

term%5Bn%5D%22%22=%22%22%281%2F2%5E1%29%2A2%5E%28n-1%29

term%5Bn%5D%22%22=%22%222%5E%28n-1%29%2F2%5E1

Subtract exponents:

term%5Bn%5D%22%22=%22%222%5E%28n-2%29

Edwin