(I) 3, 13, 23, 43, 53, 63, ...
That's the arithmetic sequence that has first term a1=3
and common difference d=10. So we use the formula for the nth
term:
an = a1+(n-1)d
Substituting a1=3, d=10.
The general term is
an = 3+(n-1)(10)
an = 3+10(n-1)
an = 3+10n-10
an = 10n-7 <--general term
Substituting n=25
a25 = 10(25)-7
a25 = 250-7
a25 = 243 <--25th element
-------------------------
(II) 3, 8, 13, 18, 23, 27, ...
That's the arithmetic sequence that has first term a1=3
and common difference d=5.
Do it the same way.
-------------------------
(III) 1, 3, 5, 7, 9, 11, 13, 15, ...
That's the arithmetic sequence that has first term a1=1
and common difference d=2.
Do it the same way.
Edwin