SOLUTION: Find the sum of the terms of a geometric sequence where the first term is 4, the last term is 324, and the common ratio is 3. U

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Question 1044698: Find the sum of the terms of a geometric sequence where the first term is 4, the last term is 324, and the common ratio is 3.
U

Found 2 solutions by MathLover1, ikleyn:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

To find the sum of a certain number of terms of a geometric sequence:
S%5Bn%5D=a%5B1%5D%281-r%5En%29%2F%281-r%29
where S%5Bn%5Dis the sum of n terms (nth partial sum),
a%5B1%5D is the first term, r is the common ratio.
if given the first term is a%5B1%5D=4, the last term is a%5Bn%5D=324, and the common ratio is r=3 than we need first to find what number is the last term:
To find any term of a geometric sequence:
a%5Bn%5D=a%5B1%5D%2Ar%5E%28n-1%29
where a[1] is the first term of the sequence, r+is the common ratio, n is the number of the term to find
324=4%2A3%5E%28n-1%29
324%2F4=3%5E%28n-1%29
81=3%5E%28n-1%29
3%5E4=3%5E%28n-1%29.........since base same, exponents must be same too, so we have
4=n-1
n=5-> so, your sequence have 5 terms
than the sum will be:
S%5B5%5D=4%281-3%5E5%29%2F%281-3%29
S%5B5%5D=4%281-243%29%2F%28-2%29
S%5B5%5D=2%28-242%29%2F%28-1%29
S%5B5%5D=2%28242%29
S%5B5%5D=484


Answer by ikleyn(52788) About Me  (Show Source):