SOLUTION: 1 - 4/5 - 3/5 - 8/17 - 5/13 - ...???? LOGICA?

Algebra ->  Sequences-and-series -> SOLUTION: 1 - 4/5 - 3/5 - 8/17 - 5/13 - ...???? LOGICA?      Log On


   



Question 1037098: 1 - 4/5 - 3/5 - 8/17 - 5/13 - ...????
LOGICA?

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
What do you want to do with it?

I'll do what I can:

SUM = 1 - 4/5 - 3/5 - 8/17 - 5/13 - ...????

SUM = 2/2 - 4/5 - 6/10 - 8/17 - 10/26 - ...????

The sequence of absolute value of numerators is 2,4,6,8,10
The sequence of absolute value of denominators is 2,5,10,17,26

2,4,6,8,10 has general term 2n
1,5,10,17,26 has general term n2+1

The general term would be -2n%2F%28n%5E2%2B1%29 except for the first
term being positive instead of negative, so we write the first term as
2-2%2F2

SUM = 2 - 2/2 - 4/5 - 6/10 - 8/17 - 10/26 - ...????

So it could be written this way:

SUM = 2+-+sum%28%282k%2F%28k%5E2%2B1%29%29%2Ck=1%2Cn%29

The next term after -10/26 (or -5/13) would be -2%286%29%2F%286%5E2%2B1%29=-12%2F%2836%2B1%29=-12%2F37

It can't be summed to infinity because it diverges when compared 
to the harmonic p-series S(1/n).

Edwin