SOLUTION: an infinite geometric series with second term -8/9 and sum 2. what is the first term?

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Question 1016990: an infinite geometric series with second term -8/9 and sum 2. what is the first term?
Answer by ikleyn(52788) About Me  (Show Source):
You can put this solution on YOUR website!
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an infinite geometric series with second term -8/9 and sum 2. what is the first term?
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a*r = -8%2F9    (1)    This is your first equation for the second term of GP.
                     Here "a"is the first term and "r" is the common ratio of the GP.

a%2F%281-r%29 = 2    (2)    This is your second equation for the sum.

From the first equation express r = -8%2F%289a%29 and substitute it into the second equation. You will get

a%2F%281+-+%28%28-8%29%2F%289a%29%29%29%29 = 2,   or

a = 2%2A%281+%2B+%288%2F%289a%29%29%29,   or

a = 2+%2B+16%2F%289a%29.

Now multiply both sides by 9a. You will get

9a%5E2 = 18a + 16,   or 

9a%5E2+-+18a+-+16 = 0.

Apply the quadratic formula to solve this quadratic equation. You will get

two roots a%5B1%5D = 8%2F3 and a%5B2%5D = -2%2F3.

The values of "r" that correspond to these values of "a" in accordance to (1), are

r%5B1%5D = %28-8%2F9%29 : 8%2F3 = -1%2F3  and  r%5B2%5D = %28-8%2F9%29 : %28-2%2F3%29 = 4%2F3.

The second r%5B2%5D = 4%2F3 has the modulus greater than 1 and therefore generates the "divergent" geometric progression. So, the second solution doesn't fit.

Now check the equality (2) for the first solution: a%5B1%5D%2F%281-r%5B1%5D%29 = 8%2F3 : %281-%28-1%2F3%29%29 = 8%2F3 : %281+%2B+1%2F3%29 = 8%2F3 : 4%2F3 = 2.  OK!

Thus there is a unique GP with the given second term and the given sum.

It is  a%5B1%5D =  8%2F3,  r%5B1%5D = -1%2F3.