SOLUTION: find the value of n if the sum of n terms of the series 11 + 33 + 99 + ... is equal to 108 251.

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Question 1012940: find the value of n if the sum of n terms of the series 11 + 33 + 99 + ... is equal to 108 251.
Answer by ikleyn(52787) About Me  (Show Source):
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find the value of n if the sum of n terms of the series 11 + 33 + 99 + ... is equal to 108 251.
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This progression is geometric with the first term 11 and the common ratio of 3.

Use the formula for the sum of the first n terms of a geometric progression:

S%5Bn%5D = a%2A%28%28q%5En+-+1%29%2F%28q-1%29%29. 

(see the lesson Geometric progressions in this site).

Substitute here a = 11 and q = 3. You will get an equation

11%2A%28%283%5En+-+1%29%2F%283-1%29%29 = 108251,   or


%283%5En+-+1%29%2F2 = 108251%2F11 = 9841,

3%5En = 2*9841 + 1 = 19683 = 3^9.

Hence, n = 9.

Answer. n = 9.