SOLUTION: sum of the numbers of the series: 6+9+21+69+261+........upto n terms

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Question 1008641: sum of the numbers of the series:
6+9+21+69+261+........upto n terms

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
For k = 1, a1 =   6 =   1+5 = 4^0+5 
For k = 2, a2 =   9 =   4+5 = 4^1+5
For k = 3, a3 =  21 =  16+5 = 4^2+5
For k = 4, a4 =  69 =  64+5 = 4^3+5
For k = 5, a5 = 261 = 256+5 = 4^4+5
...
For k = n-1, an = 261 = 4^(n-1)+5

So we add the sequence 4%5E0%2B4%5E1%2B4%5E2%2B4%5E3%2B4%5E3%2B%22%22%2A%22%22%2A%22%22%2A%22%22%2B4%5En

with the geometric series formula to n terms:

S%5Bn%5D%22%22=%22%22%28a%5B1%5D%28r%5En-1%29%29%2F%28r-1%29 with a1 = 1
and r = 4.

S%5Bn%5D%22%22=%22%22%281%284%5En-1%29%29%2F%284-1%29

S%5Bn%5D%22%22=%22%22%281%284%5En-1%29%29%2F3

S%5Bn%5D%22%22=%22%22%284%5En-1%29%2F3
 
Then we must add 5 to that n times which is the same as adding 5n

Answer:  SUM%5Bn%5D%22%22=%22%22%284%5En-1%29%2F3%5E%22%22%2B5n

Edwin