For k = 1, a1 = 6 = 1+5 = 4^0+5
For k = 2, a2 = 9 = 4+5 = 4^1+5
For k = 3, a3 = 21 = 16+5 = 4^2+5
For k = 4, a4 = 69 = 64+5 = 4^3+5
For k = 5, a5 = 261 = 256+5 = 4^4+5
...
For k = n-1, an = 261 = 4^(n-1)+5
So we add the sequence
with the geometric series formula to n terms:


with a1 = 1
and r = 4.






Then we must add 5 to that n times which is the same as adding 5n
Answer: 

Edwin