SOLUTION: If a, b, c are odd integers, then the equation ax2 + bx + c = 0 has no integer solution. How can I prove this? Sorry if its the wrong section >.<

Algebra ->  Sequences-and-series -> SOLUTION: If a, b, c are odd integers, then the equation ax2 + bx + c = 0 has no integer solution. How can I prove this? Sorry if its the wrong section >.<      Log On


   



Question 1006071: If a, b, c are odd integers, then the equation ax2 + bx + c = 0 has no integer solution.
How can I prove this?
Sorry if its the wrong section >.<

Answer by ikleyn(52788) About Me  (Show Source):
You can put this solution on YOUR website!
.
If a, b, c are odd integers, then the equation ax2 + bx + c = 0 has no integer solution.
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Proof

Write the equation in the form

ax%5E2+%2B+bx = -c.

If x is even then the left side is even, while the right side is odd. Contradiction.

If x is odd, then the left side is even, while the right side is odd. Contradiction again.

Hence, the equation has no solution(s) under the given conditions.

The proof is completed.