SOLUTION: This is at the end of our chapter where we learned about arithmetic and geometric sequences and the binomial theorem. The question is: Expand the binomial in the difference quotien

Algebra ->  Sequences-and-series -> SOLUTION: This is at the end of our chapter where we learned about arithmetic and geometric sequences and the binomial theorem. The question is: Expand the binomial in the difference quotien      Log On


   



Question 1000816: This is at the end of our chapter where we learned about arithmetic and geometric sequences and the binomial theorem. The question is: Expand the binomial in the difference quotient and simplify. I'm given [f(x+h)-f(x)] divided by h, I'm then given f(x)=x cubed. I don't get how this relates to series, sequences, their sums, or finding the Nth term, if you could explain the connection as well, I would appreciate it so much.
Found 2 solutions by josgarithmetic, KMST:
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
"... and the binomial theorem." You mostly need to expand that part in the difference quotient, specifically this part of the expression:

f%28x%2Bh%29=%28x%2Bh%29%5E3 and refer directly to the binomial theorem formula to be really formal about this. To be simpler about this, %28x%2Bh%29%5E3=x%5E3%2B3%2Ax%5E2%2Ah%2B3x%2Ah%5E2%2Bh%5E3.

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29=x%5E3
f%28x%2Bh%29=%28x%2Bh%29%5E3

I do not see how this relates to series, sequences, their sums, or finding the Nth term either.
I see how this relates to algebra in general, and polynomials in particular, and
I see how this is a sneaky introduction to derivatives,
which would belong in an early calculus lesson.
If the name of your class is pre-calculus, a sneaky introduction to derivatives may be the purpose of this problem.
%28f%28x%2Bh%29-f%28x%29%29%2Fh is the slope of the line AB that passes through points
A%28x%2Cf%28x%29%29 and B%28x%2Bh%2Cf%28x%2Bh%29%29 of the graph of f%28x%29 .
As you decrease abs%28h%29 towards zero, points A and B get closer together,
"tending to" being the same point A, and the line AB tends to being the tangent to the curve at A.
The derivative of f%28x%29 is the function