SOLUTION: x=log2x-log8x=4

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Question 1193138: x=log2x-log8x=4
Found 2 solutions by Alan3354, Edwin McCravy:
Answer by Alan3354(69443) About Me  (Show Source):
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
There is no way to use methods of algebra to solve an equation for 
an unknown that appears both inside and outside of a logarithmic, 
exponential, or trigonometric function.  The only way is to 
approximate it with a computer, calculator, or iterative method 
("educated" trial and error).

Perhaps you did not mean to have " x= " in the front as if it were
part of the equation, and meant only this equation:

log%282%2C%28x%29%29-log%288%2C%28x%29%29%22%22=%22%224

Let's convert one of the logs so we will have both logs to the same 
base.

I choose to convert log%288%2C%28x%29%29 to base 2.

You should memorize the change of base formula:

 log%28b%2C%28a%29%29=log%28c%2C%28a%29%29%2Flog%28c%2C%28b%29%29

and plug in a=x, b=8, c=2

log%288%2C%28x%29%29=log%282%2C%28x%29%29%2Flog%282%2C8%29%22%22=%22%22log%282%2C%28x%29%29%2Flog%282%2C2%5E3%29=log%282%2Cx%29%2F3

So substitute log%282%2C%28x%29%29%2F3 for log%288%2C%28x%29%29 in

log%282%2C%28x%29%29-log%288%2C%28x%29%29%22%22=%22%224


log%282%2C%28x%29%29-log%282%2C%28x%29%29%2F3%5E%22%22%5E%22%22%22%22=%22%224


Multiply through by 3

3log%282%2C%28x%29%29-log%282%2C%28x%29%29%22%22=%22%2212

2log%282%2C%28x%29%29%22%22=%22%2212

log%282%2C%28x%29%29%22%22=%22%226

By the definition of logarithms, from the above equation,
we have this:

x%22%22=%22%22%22_____%22%22%22=%22%22%22_____%22 

(You fill in those blanks, the first one with an 
eponential expression and the second with a number.

Edwin