SOLUTION: The perimeter of a rectangle is 220 meters. The length is 10 meters greater than the width. Find the dimensions of the rectangle.
length m
width
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Rectangles
-> SOLUTION: The perimeter of a rectangle is 220 meters. The length is 10 meters greater than the width. Find the dimensions of the rectangle.
length m
width
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You can put this solution on YOUR website! L= W+10 Let's use this value for Length in the formula below:
2L+2W= perimeter
2(W+10)+2W= 220 Multiply:
2W+20+2W= 220 Subtract 20 on both sides and add W on left:
4W= 200 Divide both sides by 4:
W= 50 This is the width, and the length is 10 more:
L= 50+10= 60
Proof:
2(50)+2(60)= 220
100+ 120= 220
220 = 220 We have the correct answer
