SOLUTION: Find the dimensions of a rectangle whose length is a foot longer than twice its width and whose perimeter is 44 feet.

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Question 979699: Find the dimensions of a rectangle whose length is a foot longer than twice its width and whose perimeter is 44 feet.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
w width
L length

system%28L=2w%2B1%2C+2w%2B2L=44%29

Simple substitution. You know what to do.