SOLUTION: A square has sides of length 3x cm. A rectangle is 2x cm by (x+7) cm. The area of the square is twice the area of the rectangle. Find the dimension of each figure. Pls help &#1

Algebra ->  Rectangles -> SOLUTION: A square has sides of length 3x cm. A rectangle is 2x cm by (x+7) cm. The area of the square is twice the area of the rectangle. Find the dimension of each figure. Pls help &#1      Log On


   

Question 975174: A square has sides of length 3x cm. A rectangle is 2x cm by (x+7) cm. The area of the square is twice the area of the rectangle. Find the dimension of each figure.
Pls help 😊
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Area of the square, 9x%5E2.
Area of the rectangle, 2x%28x%2B7%29=2x%5E2%2B14x.

9x%5E2=2%282x%5E2%2B14x%29.
Solve this for x,... and you can then use it to evaluate the dimensions of these figures.


9x%5E2=4x%5E2%2B28x
5x%5E2-28x=0
x%285x-28%29=0
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Zeros are 0 and 28/5. The meaningful value is 28%2F5=highlight_green%285%263%2F5%29.

Rectangle Dimensions:
2%2828%2F5%29=56%2F5=highlight%2811%261%2F5%29 and 28%2F5%2B7=28%2F5%2B35%2F5=63%2F5=highlight%2812%263%2F5%29.