Question 973975: The badminton court shown below occupies 1,456 square feet of the floor space of a gymnasium. If its length is 4 feet more than twice its width, find its dimensions.
width= ft
length= ft
The dimensions i was given on rectangle are length is <---x--->, and the width is <---2x+4--->
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The badminton court shown below occupies 1,456 square feet of the floor space of a gymnasium. If its length is 4 feet more than twice its width, find its dimensions.
width= ft
length= ft
The dimensions i was given on rectangle are length is <---x--->, and the width is <---2x+4--->
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Equation:
x(2x+4) = 1456
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2x^2 + 4x - 1456 = 0
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x^2 + 2x - 728 = 0
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(x-26)(x+28) = 0
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Positive solution:
x = 26 ft
2x+4 = 56 ft
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Cheers,
Stan H>
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