SOLUTION: the perimeter of a rectangle is 100 cm. determine the possible measures of one of knowing that the area of rectangle should be minimum 500 cm

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Question 970464: the perimeter of a rectangle is 100 cm. determine the possible measures of one of knowing that the area of rectangle should be minimum 500 cm
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
perimeter=2%28length%2Bwidth%29
Let us define some variables
L= length of the rectangle, in cm.
W= width of the rectangle, in cm.
A=area of the rectangle in square centimeters.
The way l and W were defined,
L%3E=W , and when L=W we have that special type of rectangle that we call a square.
From geometry (and real life common sense) we know that
perimeter%22%28in%22%22cm%29%22+=2%28L%2BW%29 and A=L%2AW .
From the problem, we know that
perimeter=100cm .
From all that we know,
2%28L%2BW%29=100 ---> L%2BW=100%2F2 ---> L%2BW=50 ---> L=50-W ,
and plugging the expression 50-W for L in A=L%2AW ,
we get A as a function of W :
A=%2850-W%29W <---> A=50W-W%5E2 .
That tells us that the area of the rectangle is a quadratic function of W .
From a memorized formula,
or from looking a the function transformed using algebra as shown below,
we realize that the function has a maximum for W=25 ,
when A=25%2A25=625 .
To both sides of W=25 ,, the farther we go from W=25 ,
the smaller the value for A .
Of course, we defined W , L , and A to make sense with the "real life" situation of the problem, so they are all positive, for starters.
Also since L=50-W and L%3E=W ,
50-W%3E=W ---> 50%3E=2W ---> 50%2F2%3E=W ---> 25%3E=W , so the function is defined for 0%3CW%3C=25 ,
and we get only a piece of the quadratic function,
increasing from W=almost0 to a maximum for W=25 ,
when A=25%2A25=625 .
A=50W-W%5E2<--->A=-W%5E2%2B50-625%2B625<--->A=-%28W%5E2-50W%2B625%29%2B625<---> A=-%28W-25%29%5E2%2B625
If you need an area of 500 square centimeters, you would get it when
500=50W-W%5E2 , so you solve that to find the minimum width.
Or, you say that you want A%3E=500 and use the expression
A=-%28W-25%29%5E2%2B625<--->A=-%2825-W%29%5E2%2B625 to get
-%2825-W%29%5E2%2B625%3E=500 ---> 625-500%3E=%2825-W%29%5E2 ---> 125%3E=%28W-25%29%5E2 ---> sqrt%28125%29%3E=25-W (because we know that W%3C=25<--->25-W%3E=0 ) .
Then ,

and 25-5sqrt%285%29=about22.76 .